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DAY 1: 25 May
Through this lesson, I further learnt the importance of linear geometry in the field of mathematics and how every topic in our textbook is equally important. Take today's lesson as an example, the Pythagoras Theorem we have just learnt is imediately put into us to find the distance of lines. The distance of lines and midpoints are essential for further study of mathematics and I am glad that this topic has been planned for home learning. I also feel that the videos were interactive and could make me understand the concepts quickly. In conclusion, this online learning has been a good experience for me.
DAY 2: 26 May
Today's lesson was a tiring one to find the equations for the graphic designs. The videos put up today are as informative as those posted yesterday. the concepts were interesting and I had an enjoyable time. Same as yesterday, I learnt hat topics are interconnected. For example for today, coordinates on the graph are especially essential when making circles. I also learnt that math can be related with art through this module.
Submission of Designs:
Design 3 (Optional)
xmin = -14
xmax = 14
ymin = -7
ymax = 7
y1 = 3 + sqrt (2.5^2-(x-3.5)^2)
y2 = 3 - sqrt (2.5^2-(x-3.5)^2)
y3 = (11-2x)/1/(x>=3)/(x<=4.5)
y4 = (2x-4)/1/(x>=3)/(x<=3.75)
xmin = 0
xmax = 6
ymin = 0
ymax = 6
y1 = 0.5/(x>=-5 and x<=-4)
y2 = -0.5/(x>=-5 and x<=-4)
y3 = -x - 4.5/(x>=-6 and x<=-5)
y4 = x + 4.5/(x>=-6 and x<=-5)
y5 = 0.5/(x>=-3 and x<=0)
y6 = -0.5/(x>=-3 and x<=0)
y7 = 0.5/(x>=1 and x<=5)
y8 = -0.5/(x>=1 and x<=5)
y9 = -0.25x + 1.75/(x>=5 and x<=7)
y10 = 0.25x - 1.75/(x>=5 and x<=7)
y11 =0+sqrt(16-(x-4)^2)/(x>=0 and x<=4)
y12 =0-sqrt(16-(x-4)^2)/(x>=0 and x<=4)
y13 =0+sqrt(9-(x-4)^2)/(x>=0 and x<=4)
y14 =0-sqrt(9-(x-4)^2)/(x>=0 and x<=4)
y15 =0+sqrt(16-x^2)/(x>=-4 and x<=0)
y16 =0-sqrt(16-x^2)/(x>=-4 and x<=0)
y17 =0+sqrt(9-x^2)/(x>=-4 and x<=0)
y18 =0-sqrt(9-x^2)/(x>=-4 and x<=0)
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