# 2P133

REMINDER: Please name your files 2P1XX FILENAME before uploading in case you overwrite other peoples' files!

DAY 1: 25 May

Today' lesson was refreshing and fruitful as we embarked on two new areas of coordinate geometry and learned how to calculate the midpoint on a line between two points and the distance of a lkine bewtween two points. I found calculating distance and midpoint easy as the equation is simple, only involving the x and y axis. First i looked at Distance. The formula for the distance of a line is square root of (x2-x1) square + (y2-y1) square. When i looked at this formula, i found it strangely familiar and when i went to investigate further, i realised that this is the same as the pythagoreas theorem! I realised that finding distance of a line is just taking the line as the hypotenuse of a right angled triangle with the adjacent and opposite as the y axis and the x axis! After watching the video, i learnt how to apply the formula. Next i went to look on midpoint formula. After watching the video, i found out that the midpoint formula is just (x1+x2)/2 , (y1+y2)/2. I was stuck on this before when i came across it on the textbook and i now then know how easy it is to find the midpoint. The average of the x axis would be the x coordinate of the midpoint an the average of the y axis would be the y coordinate for the midpoint. After i fully grasped both concepts, i went on to do the practices. They were easy, but i think that there are harder ones waiting for us back in class. The practices helped me to understand how to do such problems and how would the problems be set. Overall, this experience was really great and i think it is quite good as we would peacefully investigate the concepts on our own to get more benefits.

DAY 2: 26 May

Type a 100-word reflection for today's lesson and comment on your work.

Today was not as fruitful as yesterday as i did not know how to do the graphic calculator. Nevertheless, i found today's topic useful and i learnt several new stuff such as how to calculate the equation of a circle. When i flipped open the math workbook some time ago, i was intrigued by the circle on the y axis and x axis and wanted to know what is the formula to calculate it. Now i know, and am quite satisfied. However, i did not really do any of the 4 designs as after looking through all of your resources and searching everything on google, i could only make briefly about 2 rings for the olympic and could not continue. I will attempt them later to see if i can get it right. So all in all, today is not that good but is still ok.
Submission of Designs:
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